The potential energy of a mass element dm at a height a above the earth's surface is dV = (dM)gz. Compute the potential energy in a pyramid of height h, square base b x b, and mass density p.
dV = (dM)gz
V = 1/3 Bh - pyramid volume
The Attempt at a Solution
I have drawn out the dimensions and tried changed the form of the potential differential from dV = (dM)gz to dV = [1/3 (b^2)h]pgdm but I'm pretty sure it wouldn't be dm and dm transforms when you consider the entire potential of the volume with respect to the mass element. Even if it transforms to something like dh however, I would still be a factor of two off.
Thanks to anybody that helps.