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A single conservative force acting on a particle varies as:

F=(-Ax+Bx^2)iN

where A=48N/m and B=93N/m^2 and x is in meters.

Find the change in potential energy as the particle moves from x0=3.2m to x1=2.8m. Answer in units of J.

Find the change in kinetic energy of the particle between the same two points. Answer in units of J.

I tried this problem and I thought it was zero. However, the answer is not zero. I also thought the kinetic energy was -277.696. Can anybody verify this answer? Thanks.

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# Homework Help: Potential energy

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