# Potential energy

1. Feb 24, 2004

### Xamfy19

i need help for this problem.

A single conservative force acting on a particle varies as:

F=(-Ax+Bx^2)iN

where A=48N/m and B=93N/m^2 and x is in meters.
Find the change in potential energy as the particle moves from x0=3.2m to x1=2.8m. Answer in units of J.
Find the change in kinetic energy of the particle between the same two points. Answer in units of J.

I tried this problem and I thought it was zero. However, the answer is not zero. I also thought the kinetic energy was -277.696. Can anybody verify this answer? Thanks.

2. Feb 24, 2004

### jamesrc

Try this:
$$\Delta U = -\int_{x_o}^{x_f} F(x)\cdot dx$$

Last edited: Feb 24, 2004
3. Feb 24, 2004

### Xamfy19

Thanks alot

It worked. Thanks.

4. Feb 24, 2004

### Mac13

cool thx :)

Last edited: Feb 24, 2004