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Homework Help: Potential energy

  1. Feb 24, 2004 #1
    i need help for this problem.

    A single conservative force acting on a particle varies as:

    F=(-Ax+Bx^2)iN

    where A=48N/m and B=93N/m^2 and x is in meters.
    Find the change in potential energy as the particle moves from x0=3.2m to x1=2.8m. Answer in units of J.
    Find the change in kinetic energy of the particle between the same two points. Answer in units of J.

    I tried this problem and I thought it was zero. However, the answer is not zero. I also thought the kinetic energy was -277.696. Can anybody verify this answer? Thanks.
     
  2. jcsd
  3. Feb 24, 2004 #2

    jamesrc

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    Science Advisor
    Gold Member

    Try this:
    [tex] \Delta U = -\int_{x_o}^{x_f} F(x)\cdot dx [/tex]
     
    Last edited: Feb 24, 2004
  4. Feb 24, 2004 #3
    Thanks alot

    It worked. Thanks.
     
  5. Feb 24, 2004 #4
    cool thx :)
     
    Last edited: Feb 24, 2004
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