i need help for this problem. A single conservative force acting on a particle varies as: F=(-Ax+Bx^2)iN where A=48N/m and B=93N/m^2 and x is in meters. Find the change in potential energy as the particle moves from x0=3.2m to x1=2.8m. Answer in units of J. Find the change in kinetic energy of the particle between the same two points. Answer in units of J. I tried this problem and I thought it was zero. However, the answer is not zero. I also thought the kinetic energy was -277.696. Can anybody verify this answer? Thanks.