Two point charges are arranged as shown on the x axis. q1 = +7.00 nC,
and q2 = −5.00 nC. a = 25.0 cm.
Calculate the position on the x axis, outside of the charges, where the
electric potential is zero
(ignore the periods)
The Attempt at a Solution
kq1/d = -kq2/d
k(7nC)/d = -k(-5nC)/(d-25)
I get the correct answer but my question is, why is it d-25 and why is it under q2? My first approach I had.
k(7nC)/(d+25) = -k(-5nC)/d