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Homework Help: Potential function, V

  1. Mar 31, 2010 #1
    1. The problem statement, all variables and given/known data
    Determine whether or not V = xy is the correct potential function for the geometry shown in the figure: http://img268.imageshack.us/img268/446/48401266.jpg [Broken] for the region 0 < x< 1 and 0 < y < 1. Why or why not? Assume that the region between the conducting plates has a relative permittivity of εr = 3.0.

    Image for problem shown at this URL: http://img268.imageshack.us/img268/446/48401266.jpg [Broken]
    2. Relevant equations
    There are multiple equations for the potential function V. I do not know which one to use/how to use it.

    3. The attempt at a solution
    Don't really know to get started on this one. I would appreciate any help that you can provide. I just need to know how to get started. Thanks for the help!
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Mar 31, 2010 #2
    You're testing whether or not the trial function obeys laplace's equation with the correct boundary conditions.
  4. Mar 31, 2010 #3
    Ah, that makes sense Mindscape. Thank you. Ok, so I have determined that del^2(V) does in fact equal 0. What does this tell me? Is it the correct potential function? By the uniqueness principle, can I conclude that V=xy is the only potential function for this design, given the boundary conditions?
  5. Apr 1, 2010 #4
    You also need to check the boundary conditions for V(x,y):

  6. Apr 1, 2010 #5
    I thought there were 2 criteria though for determining whether or not a given potential function is the solution the DiffEQ. I have already determined that the Laplacian holds true, what is the other?
  7. Apr 1, 2010 #6
    Well, if you're going to guess a solution, you'd better make sure that it satisfies the PDE to start with, and secondly that it satisfies the actual physical conditions when all is said and done.


    is that a solution? Why or why not?

    Do you know how to find the solution from scratch if you had to? Maybe that would help you understand a little better.
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