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Potential Gradient of potentiometer wire

  1. Jun 11, 2017 #1
    1. The problem statement, all variables and given/known data
    The resistivity of a potentiometer wire is (40×10^-8) ohm-m and the area of cross section is (8×10^-6)m^2.If 0.2 amp current is flowing through the wire,then the potential gradient will be??

    2. Relevant equations
    1.Resistance=[(Resisitvity)×(Length)]/(Cross-sectional area)
    2.V=IR
    3.Potential gradient of wire= (Potential difference across wire)/(Length of wire)
    3. The attempt at a solution
    ▪Assuming the length of the wire to be l, and using formula 1,we can find the resistance of the wire.
    ▪Using formula 2,potential difference across the wire can be found,since we know the current flowing through the wire(which will obviously come in terms of l).
    ▪Using formula 3,we can get the value of potential gradient.
    Problem:My answer is coming 1Vm^-1 whereas the answer given is 0.01Vm^-1
    IF THE ANSWER GIVEN SEEMS TO BE WRONG,KINDLY REPLY SO.
     
  2. jcsd
  3. Jun 11, 2017 #2

    scottdave

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    Homework Helper
    Gold Member

    I got 0.01 V/m. Did you remember to take the powers of 10 into account?
     
  4. Jun 11, 2017 #3
    Yeah,dont worry,i got it.dumb mistake.
     
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