# Potential of Infinite Sheets of Charge and Conducting Slab

1. Sep 12, 2012

### Bthornsb

1. The problem statement, all variables and given/known data

An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge denisity σ1 = 0.39 μC/m2. Another infinite sheet of charge with uniform charge density σ2 = -0.15 μC/m2 is located at x = c = 30.0 cm.. An uncharged infinite conducting slab is placed halfway in between these sheets ( i.e., between x = 13.0 cm and x = 17.0 cm).

What is V(S) - V(P), the potentital difference between point P and point S, located at (x,y) = (23.5 cm, -17.0 cm)?

2. Relevant equations
1/4*∏*ε *∫dq/r

3. The attempt at a solution

I figured I could just use the equation I gave above and integrate to get ln(r) and subtract point S-point P, but it did not work. I just want some guidance as to how to progress. Thank you in advance, I am kind of new here so I appreciate the help.

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2. Sep 14, 2012

### jayaraneda

You must take into account the conductor between the two charges.

Use V=2*pi*k*Charge Density*d

It will be easier if you split it into pieces and then continue,

A) V(P)=2*pi*k*σ1*(d from first line of charge)
+V(p)=2*pi*k*σ2*(d from second line of charge minus the conductor)

then do the same for V(s)