1. The problem statement, all variables and given/known data The attached graphic shows a potentiometer circuit. The uniform wire AB is 100 cm long and has a resistance of 0.038 ohms/cm. The standard cell has an emf of 1.35 V. The galvanometer registers zero when the sliding contact is at L = 48.0 cm. If the sliding contact were moved to L = 56.0 cm, in what direction would electrons flow through the standard cell and why? 2. Relevant equations V = IR emf = V + Ir = Ve + Vi = L(Vo/Lo) 3. The attempt at a solution I'm really confused by this question. The only thing I've been able to figure out so far is that, using I = V/R, I equals 0.74 A when the potentiometer is in balance, and equals 0.63 A when the contact is at 56.0 cm. I'm not sure what this means though. Doesn't the potentiometer mean that no current flows when it is in balance?