Powe series of functions

  • Thread starter dan
  • Start date
  • #1
Hi, I am stuck on this problem!

Given the function, find the first four terms of the power series representation and find the domain of convergence?

function is;
(1-x)/(1-2x)^3

my calculation;
find derivatives of the function.

y'=(1-x)/(1-2x)^4
y''=(1-x)/(1-2x)^5

I am having difficulty in knowing if what I did was correct.

I'm not sure if this is how you are meant to approach it and if what I did was the correct way to go about solving the problem.

If anyone can help me in solving my problem your help will be appreciated.

Dj
 

Answers and Replies

  • #2
arcnets
508
0
Hi dan,
I think you should use Taylor's formula.
It's true you need the derivatives.
But I think your results are wrong. I get, for instance,

y'=(5-4x)/(1-2x)^4
 
  • #3
mathman
Science Advisor
8,077
547
Use the binomial expansion to get a series for (1-2x)-3, multiply the first few terms by (1-x). It will converge for |x|<1/2.
 
  • #4
Your derivatives are not exactly correct. You need to use the quotient rule and the chain rule in this case.
Remember the quotient rule y' = (vu' - uv')/v^2.
Now let u = (1-x) and v = (1-2x)^3.
u' = -1, v' = -6(1-2x)^2 (chain rule).

therefore y' = (-(1-2x)^3-(-6)(1-x)(1-2x)^2)/(1-2x)^6
= ((1-2x)^2(5-4x))/(1-2x)^6
= (5-4x)/(1-2x)^4
 

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