I am trying to relate two concepts, Power and Kinetic Energy, using a small DC motor.(adsbygoogle = window.adsbygoogle || []).push({});

Given the no-load max angular velocity w (rads/s) of the motor and the current drawn (A) at a given voltage (V) the power being used (P) in Watts is:

P = V x A

Given the no-load max angular velocity w (rads/s) and assuming the armature is a cylinder of uniform density, known radius (r) and known mass (m) the kinetic energy (Joules) of the armature is given by

KE = 1/2 I w^2

Where I is the moment of intertia given by

I = 1/2 m r^2.

So I have the Watts (P) being "consumed" and KE in Joules. Can I use this to calculate the efficiency of conversion from electrical to mechanical (under the stated conditions)?

Can I simply express that in 1 second the efficiency is KE / P x 100?

Basically, I am having trouble reconciling the time dimension of Power (J/s)

Thanks in advance.

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# Power and kinetic energy relationship in a small DC motor

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