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Power and resistance problem

  1. Oct 12, 2005 #1
    Suppose that a person has a resistance of 13.0 kiloohms as part of a circuit which passes through his hands. This person accidentally grasps the terminals of a power supply with a potential difference of 16.0 V.
    PART A:If the internal resistance of the power supply is 2100 ohms , what is the current through the person's body?
    I calculated the current to be 1.06×10−3 A by using the equation I = V/(R_p + R_i)
    PART B: To find the power dissipated in his body I thought you use the equation P = I*V so P =(1.06*10^-3 A)*(16.0V) which gave me 1.70*10^-2 which is wrong. What I am doing wrong??
    Thank you for your help
     
  2. jcsd
  3. Oct 12, 2005 #2

    hotvette

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    You assumed that the 2 resistances are in series. Are they?
     
  4. Oct 13, 2005 #3

    hotvette

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    I noticed the same post in the Intro Physics section. You should avoid double posts.
     
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