Power and Tq Needed to keep a car rooling at speed

In summary, the conversation is about determining the power and torque needed to keep a car rolling at speed, including factors such as road load force, drag coefficient, and weight of the car. The formula for calculating these forces is given, but the units are not provided. The speaker also asks for help in accounting for factors such as slope, altitude, and temperature changes. They then share their own calculations and conclude that it takes about 60 horsepower to maintain a speed of 75 mph on a 6% grade with a 3300-pound car. They also note that their car has 100 horsepower and 200 ft-lbs of torque, which seems about right based on their calculations.
  • #1
Dieseltwitch
12
0
Power and Tq Needed to keep a car rolling at speed

Ok so I am working on a personal project to formulate hybrid systems for a given car.
Before i can do any of the electrical math however i need to find how much power and tq it takes to no only get the car moving but keep it moving (flat & any given degree of climb)

I found a site that shows me some basic stuff on how to find the forces acting on a car by the air at a given speed

Road Load Force = a + bv + cv^2

a = Resistance from brake pads, or friction in the wheel bearings
b = Friction of the tires
c = Drag Coefficient
v = VelocityThe formula is great I'm sure... BUT THEY DIDN'T GIVE ANY DAMN UNITS!
- some one help me please.
- How do you tie the Dc into every thing? I did some looking around and found a dc 0.31 for my car
- I also have no idea how to account for a car going up a slope, any one?
- How can i account for alt changes and temp changes? ( i think i need a simple formula for Pressure density)I did find a quick and easy formula and found that i have about 446n acting on the front of the car at 120 kph or 75 mph. this in turns translates to ABOUT 16kw of power needed to keep the car at speed. what I'm wondering is where is this power applied. is this motor power? or just power needed at the wheel? i know from school that through gearing HP is divided by the gear ratio and Tq is multiplied by the gear ratio... so how to i translate the 16kw it to Tq and HP at the Motor taking into account the tires?

Thank you for any help you guys/gals have to give. let me know if you need any other numbers.

just for Ref the car is a 05 Jetta TDI and weighs in at 3,300 lbs or 1,500 kgs
 
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  • #2
Think i figured it out.

Ok so here is what i did... (CHECK ME and let me know if i messed it up)
First i needed to find the force on my car. being that the force changes dynamically with the speed of the car.

I ran the car up to 85 mph and pushed in the clutch. Then I let it fall from 85 mph to 80 mph and started a timer. I then waited till it fell to 70 mph.

80 to 70 mph = 15 seconds
Avg Speed = 75 mph (121 kph)
Acceleration = .9778 f/s/s (.2980 m/s/s)

Knowing the acceleration from 80 to 70 mph i can then find the force acting on the front of the car

F = M*A

Mass of the Car = 3300 lbs or 1497 kg


F = 1497*.2980
F = 446 N

Power needed to Maintain 75mph (121 kph) = F * Av
Av = Avg speed (m/s) = 34 m/s

Power = 446 * 34

Power = 15,000 Watts (15 Kw) or 20 Hp

So from what i found it take 20 Hp to maintain 75 mph on flat ground (where i tested the forces on the car)

Now for the hills...

the Weight (force acting strait down) of my car:

1497kg * 9.8 m/s = 14671 N

For this i will use a 6% grade or 3.43 degs
the force traveling parallel to the road (pushing car back down the hill)

Fp = sin(deg) * Fd

Fp = Force parallel (N)
deg = 3.43
Fd = Force down or Weight (N)

Fp = sin(3.43)*14761

Fp = 878 N

By adding tFp to the force found on level road i think i came up with the force need to keep the car traveling at 75 mph up a 6% grade.

446 n +878 n = 1323.87 n

with the same speed (34 m/s) this comes out to and additional 30 kw or 40 hp for an over all need of 45 kw (60hp) to maintain 75 mph @ 6% grade with a 3300 lbs

So that's what "I" got let me know if i got this right.

just as a note. I am about 3/4 throttle at 75 up a 6% slope (avg highway mtn pass here in Colorado) my car has 100 hp and 200 ft-lbs of tq. given some room for power loss do to the 9000 ft above sea level. 60 hp seams about right
 
  • #3


I would first like to commend you for taking on this personal project and for seeking out help and clarification on the units and calculations involved. It shows a true dedication to understanding the science behind a car's performance.

To answer your question, the power and torque needed to keep a car rolling at a certain speed depends on various factors such as the car's weight, aerodynamics, road conditions, and slope. The formula you have found is a good starting point, but it is important to note that it is a simplified model and may not account for all the variables.

To determine the power needed at the motor, you can use the formula: Power = force x velocity. In this case, the force would be the road load force calculated using the formula you found, and the velocity would be the car's speed.

To determine the torque needed at the motor, you can use the formula: Torque = force x distance. In this case, the force would again be the road load force, and the distance would be the radius of the car's wheels.

It is also important to consider the efficiency of the car's drivetrain, as not all the power and torque generated by the motor is transmitted to the wheels. Gearing and other mechanical losses can significantly affect the power and torque needed at the motor.

To account for changes in altitude and temperature, you would need to consider the changes in air density, which can affect the drag force acting on the car. You can use the ideal gas law to calculate air density, using the temperature and pressure at different altitudes.

Overall, the calculation of power and torque needed to keep a car rolling is a complex process that involves many variables. I would suggest consulting with automotive engineers or using more advanced modeling software to get a more accurate estimation. Good luck with your project!
 

1. What is the difference between power and torque?

Power and torque are both measures of a car's ability to move, but they represent different aspects of that movement. Power is a measure of how quickly work can be done, while torque is a measure of the twisting force that can be applied. In simple terms, power is how fast the car can go, while torque is how effectively it can accelerate.

2. How do power and torque affect a car's performance?

The power and torque of a car affect its acceleration, top speed, and overall performance. A car with high power and torque will be able to accelerate quickly and reach higher speeds, while a car with lower power and torque will have slower acceleration and a lower top speed.

3. How is power and torque calculated?

Power is calculated by multiplying the torque at a given engine speed by the engine speed itself. Torque is calculated by measuring the amount of force applied to the crankshaft and multiplying it by the distance from the center of rotation to the point where the force is applied.

4. What factors affect the power and torque needed to keep a car rolling at speed?

The power and torque needed to keep a car rolling at speed are affected by several factors, including the weight of the car, the aerodynamics of the car, the road conditions, and the engine's efficiency. Heavier cars require more power and torque to maintain speed, and cars with better aerodynamics require less power and torque.

5. Can a car have too much power and torque?

While having high power and torque can improve a car's performance, it is possible for a car to have too much power and torque for its intended use. This can lead to issues with handling and control, as well as potentially damaging the car's engine and drivetrain. It is important for car manufacturers to carefully balance power and torque to create a well-performing and reliable vehicle.

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