You push a 10 kg box up a rough ramp at a constant speed of 2 m/s.
vi-vf=0 since constant which means a=0
a. What is the rate at which you do work on the box? b. What is the rate at which gravity does work on the box? c. What is the rate at which friction does work on the box? d. What is the rate at which the net force does work on the box?
I am not certain believe I should find distance traveled first..
Then the rest of work might be simple..
Wgravity=mg cos 180(yf-yi)
P = F*v = rate of work done
The Attempt at a Solution
Ffric= uk*mgcos(theta)= .4(10kg)(9.8)cos(15)=.380N?
2ad=vf^2-vi^2 => vf^2-vi^2*2/a
which I think would = 0 so that must be wrong
I think I am on the wrong track, any help would be appreciated. Thank you!