i got R equivalent = 3.2 ohmAnswer these questions in order and you'll get there.
1.) What is the equivalent resistance of this circuit?
2.) What is the voltage across that equivalent resistance?
3.) What is the current through the right branch of the circuit? (Mr. Ohm will help you here)
Now you're ready to compute the power dissipated in that resistor.
thats exactly what i did ;)Ack! You know what, I made the problem a little too simple in my head. You're right about the equivalent resistance and the voltage across it. That means that the voltage across the 16 Ohm resistor is 32V, so there's 2A going through it. So the other 8A goes into the other resistors. You can apply Kirchhoff's Voltage Law at this point to get the voltage across the 6 Ohm resistor.