- #1
Pi Face
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http://imgur.com/WO1zq
I tried the loop rule method but I couldn't get it to work since I had 2 unknowns (currrent and R1/R2)
I know that for resistors in series, the current through both are the same. Also, R1 should equal R2, beecase they need to dissipiate the same power. This means the equivalent resistance of R1 and R2 is just half of either one (R1/2). So, the total equivalent resistance is 2k+R_1/2.
I also know that the voltage across two resistors in parallel is the same, so V across R1 and R2 are equal, meaning the current through both are equal as well. Using the junction rule, if I1 is the current through the first resistor Rb, then the current through R1 and R2 is I_1/2 for each.
I think I know a fair amount about the circuit but I'm not sure how to combine all of it into something sensible...
I tried the loop rule method but I couldn't get it to work since I had 2 unknowns (currrent and R1/R2)
I know that for resistors in series, the current through both are the same. Also, R1 should equal R2, beecase they need to dissipiate the same power. This means the equivalent resistance of R1 and R2 is just half of either one (R1/2). So, the total equivalent resistance is 2k+R_1/2.
I also know that the voltage across two resistors in parallel is the same, so V across R1 and R2 are equal, meaning the current through both are equal as well. Using the junction rule, if I1 is the current through the first resistor Rb, then the current through R1 and R2 is I_1/2 for each.
I think I know a fair amount about the circuit but I'm not sure how to combine all of it into something sensible...