I was looking at the mass-energy relationship equation, which by taking the derivative I would think that you you should get a power-energy relationship. What I get is:(adsbygoogle = window.adsbygoogle || []).push({});

[itex]P = \frac{mc^2}{2\sqrt{1-\frac{v^2}{c^2}}}*2a[/itex]

If this were to be true, a particle without acceleration would have no power, and thus release no energy. Or, it could be that all of the energy is instantaneously released and shows no power. Can someone help me where I went wrong in this?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Power-Energy Relationship

**Physics Forums | Science Articles, Homework Help, Discussion**