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http://ajubi.com/pf.png

Xl = 2 * pi * f * l = 3.0159j Ω

Z = 60 + 3.0159j = 60.0758 phase-angle 2.8776

I = 240 / 60.0758 = 3.995 A

True Power = I^2 * R = 15.9596 * 60 = 957.576 W

Reactive Power = I^2 * X = 15.9596 * 3.0159 = 48.1326 VAR

Apparent Power = I^2 * Z = 15.9596 * 60.0758 = 958.7857 VA

Then for the capacitor:

Xc = V^2 / Q = 57600 / 48.1326 = 1196.6941 Ω;

C = 1 / ( 2 * pi * f * Xc) = 1 / ( 2 * pi * 60 * 1196.6941) = 2.3557 nF

But this value for the capacitor seems way too small :/ Thanks for any help!