1. The problem statement, all variables and given/known data A lightbulb marked 75W at 120V is screwed into a scoket at one end of a long extension cord, inw hich each of the two conductors has resistance 0.8 ohms. The other end of the extension cord is plugged into a 120 V-outlet. Draw a circuit diagram and find the actual power delivered to the bulb in this circuit. 2. Relevant equations IR = deltaV P = I^2R 3. The attempt at a solution Well, first I tried to find the current through the circuit: I = 120 V/ R1 + R2 = 120 V/1.6 ohms = 75 A Seemed all right, So I found the power delivered to the bulb: P = (75)^2(1.6) = 9000 W = 9 kW This doesn't seem very logical to me. Haha. Perhaps I mixed up "conductor" with resistor, I'm not sure what a conductor is...? But it shouldnt make much of a difference. I tried it with the resistors in parallel but that didnt help, of course.