Power Loss Due to Resistance

  • Thread starter mlsohani
  • Start date
  • #1
mlsohani
11
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Homework Statement



A high-voltage transmission line with a resistance of 0.345 ohms /km carries a current of 1.05 kA. The line is at a potential of 600 kV at the power station and carries the current to a city located 173 km from the power station.
A>What is the power loss due to resistance in the line?
B>What fraction of the transmitted power does this loss represent?




Homework Equations



P=IV
p=V^2(R)


The Attempt at a Solution



part A>I used the kilometers to figure out the resistance from the distance. I then tried pluging in the values into the equations but the answer is not working.

partB> In order to calculate the fraction I want to make sure I am setting hte first part of the equation correctly. But I assume that you subtract the power loss from the original power.
 

Answers and Replies

  • #2
RoryP
76
0
your second equation is wrong, its P=(V^2)/R
maybe that might help?
also could you tell me the answer to see if i got it right =]
cheers
 
  • #3
mlsohani
11
0
OK I keep getting it wrong

so I now tried: P=I^2*R

I did 0.345ohms/km * 173 km= 59.685

Then I did P=I^2*R to get> (1.05kA*1.05kA)*(59.685ohms)= 65.8 kW

BUT it keeps telling me I am WRONG!!! PLease help!!
 
  • #4
ImAnEngineer
209
1
I did 0.345ohms/km * 173 km= 59.685

P = I² *R = (1.05kA*1.05kA)*(59.685ohms)= 65.8 kW

You might wanna plug that into your calculator again :P

(1,05 * 10³)² * 0.345 * 173 = 65.8 MW


Is that the correct answer? (sounds like a little too much to me but I don't know...)
 

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