1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Power of a complex number

  1. Mar 18, 2008 #1
    Im trouble getting the correct answer for z^23 where z=1+1
    The answer in the back of the book says its 2^16e(i8pie)
    But z=|z|^(n)e(i(n)theta) Therefore the hypotenuse which is 2^(1/2) when multiplied by 23
    should be 2^(23/2) not 2^(16)
     
  2. jcsd
  3. Mar 18, 2008 #2
    You're right, of course. I don't know from where the book got 216.
     
  4. Mar 19, 2008 #3

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    … 32 ≠ 23 …

    Hey guys!

    It's obviously z^32 … :rolleyes:

    (btw, if you type alt-p, it prints π)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Power of a complex number
Loading...