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Homework Help: Power of a complex number

  1. Mar 18, 2008 #1
    Im trouble getting the correct answer for z^23 where z=1+1
    The answer in the back of the book says its 2^16e(i8pie)
    But z=|z|^(n)e(i(n)theta) Therefore the hypotenuse which is 2^(1/2) when multiplied by 23
    should be 2^(23/2) not 2^(16)
  2. jcsd
  3. Mar 18, 2008 #2
    You're right, of course. I don't know from where the book got 216.
  4. Mar 19, 2008 #3


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    … 32 ≠ 23 …

    Hey guys!

    It's obviously z^32 … :rolleyes:

    (btw, if you type alt-p, it prints π)
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