Power of a complex number

565
2
Im trouble getting the correct answer for z^23 where z=1+1
The answer in the back of the book says its 2^16e(i8pie)
But z=|z|^(n)e(i(n)theta) Therefore the hypotenuse which is 2^(1/2) when multiplied by 23
should be 2^(23/2) not 2^(16)
 
737
0
You're right, of course. I don't know from where the book got 216.
 

tiny-tim

Science Advisor
Homework Helper
25,799
242
… 32 ≠ 23 …

Im trouble getting the correct answer for z^23 where z=1+1
The answer in the back of the book says its 2^16e(i*pie)
Hey guys!

It's obviously z^32 … :rolleyes:

(btw, if you type alt-p, it prints π)
 

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