Power of a complex number

  • Thread starter Ry122
  • Start date
  • #1
565
2
Im trouble getting the correct answer for z^23 where z=1+1
The answer in the back of the book says its 2^16e(i8pie)
But z=|z|^(n)e(i(n)theta) Therefore the hypotenuse which is 2^(1/2) when multiplied by 23
should be 2^(23/2) not 2^(16)
 

Answers and Replies

  • #2
737
0
You're right, of course. I don't know from where the book got 216.
 
  • #3
tiny-tim
Science Advisor
Homework Helper
25,832
251
… 32 ≠ 23 …

Im trouble getting the correct answer for z^23 where z=1+1
The answer in the back of the book says its 2^16e(i*pie)
Hey guys!

It's obviously z^32 … :rolleyes:

(btw, if you type alt-p, it prints π)
 

Related Threads on Power of a complex number

  • Last Post
Replies
6
Views
1K
Replies
4
Views
2K
  • Last Post
Replies
2
Views
857
  • Last Post
Replies
5
Views
1K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
8
Views
3K
  • Last Post
Replies
3
Views
954
Replies
2
Views
2K
Top