(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A fire hose for use in urban areas must be able to shoot a stream of water to a maximum height of 35 m. The water leaves the hose at ground level in a circular stream 3.5cmin diameter.

What minimum power is required to create such a stream of water? Every cubic meter of water has a mass of 1.00*10^3 kg.

2. Relevant equations

P=W/t

W=Fd

V(of cylinder)=pi*r^2*h

3. The attempt at a solution

r=.0175m

v=pi*(.0175)^2*35

=.033674 m^3 then, mass= 33.67kg

w=(33.67)*g*35=11550 N

but then I'm stuck because I don't know what t is...

I tried v=v(0)+at, from which I got

P=m*a^2*D/v(0)

but now, I don't know how to get v(0)...

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# Power of Fire hose

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