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Power output of a car's engine

  1. Dec 1, 2008 #1
    A 2400 pound car ascends a 10 degree slope at 30 miles per hour. If the overall efficiency is 70 percent, the power output at 70 percent efficiency is 47.7 horsepowers.

    By the formula, Power=(force)(velocity) with 1 horsepower=550 ft*lb/s , the power output at 70% efficiency is 23.38 horsepowers.

    Can someone explain why it should be 47.7 horsepowers?
  2. jcsd
  3. Dec 1, 2008 #2

    Doc Al

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    Staff: Mentor

    Power = (force)(velocity) will give you the power you need to move the car. You have to find the engine power that will produce the needed power considering that only 70% is useful power. (You took 70% of the power you need, not 70% of the engine power.)
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