# Power Plant Efficiency

1. Apr 20, 2010

### kboykb

1. The problem statement, all variables and given/known data

(c13p30) A steam-electric power plant delivers 900 MW of electric power. The surplus heat is exhausted into a river with a flow of 6.29×10^5 kg/s, causing a change in temperature of 1.03 oC. What is the efficiency of the power plant (in % Don't enter a unit.)?

2. Relevant equations

Not sure with this one. Efficiency = 1 - Tc/Th, or Efficiency = W/Qh

3. The attempt at a solution

900MW = 900,000,000 J/s

900,000,000 J/s / 629,000 kg/s = 1430.8

1.03 Deg C = 274.18 K

274.18 K / 1430.8 = .19

So 19%

2. Apr 21, 2010

### Filip Larsen

As I read the problem text, cooling water leaves the plant with the given mass flow rate and with the given temperature increase. Knowing the heat capacity of water you should be able to calculate how much power is lost via the cooling water, so the efficiency must be how much 900 MW are relative to the total output of the plant (900 MW + loss). Doing that calculation you should get around 25%.

3. Apr 22, 2010

### kboykb

That was the answer, thanks :-)

Also after seeing what you said I figured out how to do it

I was factoring in the specific heat (4184) or using my formulas correctly.