A wire of resistance 5.0 Ω is connected to a battery whose emf ε is 2.0 V and whose internal resistance is 1.0 Ω. In 2.0 min, how much energy is (a) transferred from chemical to electrical form in the battery, (b) dissipated as thermal energy in the wire, and (c) dissipated as thermal energy in the battery?
P=iE(the fancy E)
The Attempt at a Solution
I am having trouble finding the current, so I cannot find power.
I am using i=2.0V/(5.0+1.0)=0.333A
then I get Vb-Va=(0.333Ax5.0)
the answer for part a) is 80J
when I use P=iV I don't get that answer...
If I could make it more clear...I can, just post!