(adsbygoogle = window.adsbygoogle || []).push({}); You can run up a set of stairs (2.55m) in 2.94s and your body mass is 59.5kg. After hearing about this, the local power company wants to contract you as the next power source. If you were able to sustain your power output for one full hour (and magically have it transferred without any losses to electrical power) and the power company can charge $0.0922 for a kWh, what could they get for an hour of your time? What could they get for your 40-hour workweek? What could they get for your 48-week work year?

-First I calculated the work, then with that (and time) the power.

Work = (mass)(gravity)(distance)

Work = (59.9kg)(9.81m/s^2)(2.55m)

Work = 1488.42 J

Power = 1488.42 J / 2.94s

Power = 506.27W

-Next I changed Watts to Kilowatts.

506.27W x 1kW / 1000W = 0.50627kW

-Then I calculated the money you would make in 1 hour.

0.50627kW / $0.0922 = $5.49

-Then I calculated the money you would make in 40 hours.

(0.50627kW)(40) / $0.0922 = $219.64

or ($5.49)(40) = $219.6

-Then I calculated the money you would make in 48 weeks.

(0.50627kW)(40)(48) / $0.0922

(0.50627kW)(1920) / $0.0922 = $10542.72

------------------------------------------------------------

Did I do everything correct? I am most concerned about calculating the money. I used division, maybe I should multiply? Help me with my sigfigs perhaps (I am horrible with the rules)? Please share your advice so I can have this question 100% right :). Thanks!

-Jay

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Power Question Help

**Physics Forums | Science Articles, Homework Help, Discussion**