mezarashi said:g = 9.79 meters per second per second
And hint about volume. The volume doesn't matter in this energy problem. Just know for later reference that 1000 liters of water = 1000 kg = 1 cubic meter.
The water output of a 2.0 hp electric motor can be calculated by multiplying the motor's horsepower by the constant 1.36. This will give you the motor's output in gallons per minute (gpm). For example, a 2.0 hp electric motor would have a water output of 2.72 gpm (2.0 hp x 1.36 = 2.72 gpm).
The formula for calculating the water output of an electric motor in horsepower (hp) is: hp = (gpm x psi) / 1714. This formula takes into account the motor's gallons per minute (gpm) and the pressure (psi) it is operating at, and divides it by the constant 1714.
Yes, the water output of a 2.0 hp electric motor can be increased by either increasing the motor's horsepower or by increasing the pressure at which it operates. However, it is important to note that increasing the pressure beyond the motor's recommended limit can cause damage to the motor and should be done with caution.
The size of the impeller does not directly affect the water output of an electric motor. However, the size and design of the impeller can impact the motor's efficiency and ultimately affect its water output. A larger or more efficient impeller can increase the motor's output, while a smaller or less efficient impeller can decrease the output.
Yes, there are a few factors that can affect the accuracy of calculating the water output of an electric motor. These include variations in pressure and flow rate, as well as the efficiency and condition of the motor itself. It is important to regularly maintain and calibrate the motor to ensure accurate calculations of its water output.