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Homework Help: Power rule for antiderivatives

  1. Oct 30, 2005 #1
    I am taking an Architectural Geometry class, and have only had Precal. We just started antiderivatives (I understand regular derivatives), and had a question:

    I have to find the antiderivative of

    (-5/12 x^4) + (10/3 x^3) - (103/12 x^2) + (23/3 x)

    I think I use the power rule for antiderivates...so far i have the first function to be

    (-5/12 x^5)/(5)

    is that right? if so, does it simplify to -.083x^5? This is where i get confused. Later on I will need to plug in a variable for x. I just wanted to make sure that I am doing this right so far. Thank you.
  2. jcsd
  3. Oct 30, 2005 #2
    yes that is right but if you simpifly it it is just -x^5/12
  4. Oct 30, 2005 #3
    Ok, thanks for the reply. If that's the case, does that make the rest of the equation:

    (-x^5) / 12 + (5x^4)/6 - [(103x^3)/12) / 3] + [(23x^2)/3) /2 ]

    Thanks again.
  5. Oct 30, 2005 #4
    Yes, but you can simplify. I'll take one of your terms.

    What's [tex]\frac{103}{12}*\frac{x^3}{3}[/tex]?
  6. Oct 30, 2005 #5
    it would be 103x^3 / 36 . Or do you want it simplified more?
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