1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Power rule for antiderivatives

  1. Oct 30, 2005 #1
    I am taking an Architectural Geometry class, and have only had Precal. We just started antiderivatives (I understand regular derivatives), and had a question:

    I have to find the antiderivative of

    (-5/12 x^4) + (10/3 x^3) - (103/12 x^2) + (23/3 x)

    I think I use the power rule for antiderivates...so far i have the first function to be

    (-5/12 x^5)/(5)

    is that right? if so, does it simplify to -.083x^5? This is where i get confused. Later on I will need to plug in a variable for x. I just wanted to make sure that I am doing this right so far. Thank you.
  2. jcsd
  3. Oct 30, 2005 #2
    yes that is right but if you simpifly it it is just -x^5/12
  4. Oct 30, 2005 #3
    Ok, thanks for the reply. If that's the case, does that make the rest of the equation:

    (-x^5) / 12 + (5x^4)/6 - [(103x^3)/12) / 3] + [(23x^2)/3) /2 ]

    Thanks again.
  5. Oct 30, 2005 #4
    Yes, but you can simplify. I'll take one of your terms.

    What's [tex]\frac{103}{12}*\frac{x^3}{3}[/tex]?
  6. Oct 30, 2005 #5
    it would be 103x^3 / 36 . Or do you want it simplified more?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Power rule for antiderivatives
  1. Power rule (Replies: 9)

  2. Power rule (Replies: 10)