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orangeincup
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Homework Statement
A power screw with a pitch of 1 mm is directly coupled to a stepper motor rotating at 60 rpm. If
the efficiency of the power screw is 35%, what is the stepper motor torque required to raise a
4450 N (1000 lb) load?
Homework Equations
P=τ*ω
τ=F*r
The Attempt at a Solution
60rpm*2∏/60=6.28 rad/s
τ=4450*(.0005)=2.22 N-m (I assume this is wrong)
The answer is suppose to be 2.023 N-m