- #1

- 166

- 0

1. The pressure device described in the pic needs to apply a force of 10kN on the 'square product' below in order to work. The worker can apply 100N force while the 'arm' is 350mm.

Assuming the friction (mew) can change from 0.05 to 0.15 and the thread is square (alpha=0) design a screw for minimum turns.

2. Sy=210 MPa, n (safety coefficient)=3, N=1 (number of 'starts' is it called?), find the screw max length against collision

I'm still in 1, im not sure how to look at it. can someone give me a head start in this question? how do you create an equation for minimum turns?

thanks