Power series of ln(1+x)

  • Thread starter donutmax
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  • #1
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hi!

are the following power series equivalent?

ln(1+x)=[tex]\sum_{n=0}^{\infty} \frac{(-1)^n n! x^{n+1}}{(n+1)!}[/tex]
=[tex]\sum_{n=0}^{\infty} \frac{(-1)^n x^{n+1}}{n+1}[/tex]
 

Answers and Replies

  • #3
CRGreathouse
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[tex]\frac{(-1)^n n! x^{n+1}}{(n+1)!}=\frac{(-1)^n x^{n+1}}{(n+1)!/n!}=\frac{(-1)^n x^{n+1}}{(n+1)}[/tex]
 
  • #4
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[tex]\frac{(-1)^n n! x^{n+1}}{(n+1)!}=\frac{(-1)^n x^{n+1}}{(n+1)!/n!}=\frac{(-1)^n x^{n+1}}{(n+1)}[/tex]
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