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I need to find [tex] \frac{1}{i+z} [/tex] as a power series in z.

I want to know if am doing this right.

If i use the taylor series here by doing

[tex]

f(z) = z^i

[/tex]

[tex]

f'(z) = i z^{-1} z^i

[/tex]

[tex]

f''(z) = i (i-1) z^{-2} z^i

[/tex]

This taylor series is just for z= i +1, but i tried using it for my problem but i dont seem to get the right answer.

this is the taylor series that i should be using but how do i find f(i) here?

[tex]

f(z) = f(i) + f'(i) (z-i) + f''(i) (z-i)^2 + \cdots

[/tex]

cheers

I want to know if am doing this right.

If i use the taylor series here by doing

[tex]

f(z) = z^i

[/tex]

[tex]

f'(z) = i z^{-1} z^i

[/tex]

[tex]

f''(z) = i (i-1) z^{-2} z^i

[/tex]

This taylor series is just for z= i +1, but i tried using it for my problem but i dont seem to get the right answer.

this is the taylor series that i should be using but how do i find f(i) here?

[tex]

f(z) = f(i) + f'(i) (z-i) + f''(i) (z-i)^2 + \cdots

[/tex]

cheers

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