# Power Series Representation

1. Jul 8, 2010

### muddyjch

1. The problem statement, all variables and given/known data
F(x)=∫(0 to x) tan^(-1)t dt. f(x)= infinite series ∑n=1 (-1)^(en)(an)x^(pn)?
en=?
an=?
pn=?
I know en = n-1

2. Relevant equations

3. The attempt at a solution
1/(1 - t) = ∑(n=0 to ∞) t^n.

Let t = -x^2:
1/(1 + x^2) = ∑(n=0 to ∞) (-1)^n * x^(2n).

Integrate both sides from 0 to x:
arctan x = ∑(n=0 to ∞) (-1)^n * x^(2n+1)/(2n+1).

Now that we have a series for arctan x...
f(x) = ∫(0 to x) arctan t dt
= ∫(0 to x) [∑(n=0 to ∞) (-1)^n * t^(2n+1)/(2n+1)] dt
= ∑(n=0 to ∞) (-1)^n * [∫(0 to x) t^(2n+1)/(2n+1) dt]
= ∑(n=0 to ∞) (-1)^n * x^(2n+2)/[(2n+1)(2n+2)].

Shifting indices up one unit, we have
f(x) = ∑(n=1 to ∞) {(-1)^(n-1)/[(2n-1)(2n)]} x^(2n).

This gives me
en = n-1
an=1/(2n(2n-1))
pn = 2n

however an and pn are wrong. where am i going wrong?

2. Jul 8, 2010

### vela

Staff Emeritus
Your work looks okay to me, and your answer matches what Mathematica spits out. Why do you think it's wrong?