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- Thread starter TyErd
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Dick

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Mark44

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No. What I would do is find the power series for log(1 + 2x), which is simply a matter of a substitution, and then determine the interval of convergence of the new series.## Homework Statement

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## Homework Equations

## The Attempt at a Solution

I'm not exactly sure how to do this question. Is it an interval of convergence question where i simply let log(1+2x) < 1 and solve for x??

BTW, calculus-type problems like this should not be posted in the Precalc section.

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Dick

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No. What I would do is find the power series for log(1 + 2x), which is simply a matter of a substitution, and then determine the interval of convergence of the new series.

BTW, calculus-type problems like this should not be posted in the Precalc section.

I don't think it's even much of a precalc question. See my previous post.

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Mark44

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I agree that it's not a difficult problem, but being about series and convergence, it seems a better place for it is in the Calculus & Beyond section.I don't think it's even much of a precalc question. See my previous post.

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Dick

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I agree that it's not a difficult problem, but being about series and convergence, it seems a better place for it is in the Calculus & Beyond section.

Your choice, of course. But I don't think you need any convergence tests to answer the question. x is a number, 2x is a number.

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so your saying the answer is simply |2x| < 1?

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No. What I would do is find the power series for log(1 + 2x), which is simply a matter of a substitution, and then determine the interval of convergence of the new series.

BTW, calculus-type problems like this should not be posted in the Precalc section.

Okay I understand how to do interval of convergences but how would I get the new series through substitution?

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