All resistors, R1 through R6, have the same resistance R. What is the power delivered by the batteries to R6? I worked it like this first... I saw two junctions, the nodes at the left and right where all three connections meet. I figured I1, I2 and I3 would meet here, combine, then split back up along the connections in the other direction as I = ((I1 + I2 + I3)/3). Power = I^2R, so I solved as (I3 - ((I1 + I2 + I3)/3))^2*R6... but mainly I have only a lot of pictures to prove that, and it's not right at all... I got some help and redrew it like this. Someone explained kirchoff's rules for loops to me briefly, and that I have to add up all the power contributions along each loop, then set them to 0. I simplify and solve simultaneous equations, also using I3 = I1 + I2. I will update with my progress... any advice would be expressly appreciated.