Power to lift skiers up hill

[jfleury45]

1. A T-bar tow is required to pull 89 skiers up a 600 m slope inclined at 15° above horizontal at a speed of 2.5 m/s. The coefficient of kinetic friction is 0.06. Find the motor power required if the mass of the average skier is 65 kg.




2. w=F*d
P=F*v



3. I found the normal force to be 615.923 N I then found the frictonal force to be 36.955N. Where do i go from here?

 

[robb_]

If you know the frictional force, how much work does it do on the skier? Are there any other forces doing work on the skier?

 

[m2003]

Based on the information provided, the next step would be to calculate the total work done (W) by the T-bar tow. This can be done using the equation W = F*d, where F is the total force required to pull the skiers up the slope and d is the distance traveled (600 m in this case).

To find the total force, we need to consider the forces acting on the skiers: the force of gravity pulling them down the slope, the normal force pushing them up the slope, and the frictional force opposing their motion. Since the skiers are being pulled up the slope at a constant speed, the net force must be zero. This means that the force of gravity must be balanced by the normal force and the frictional force.

We already know the normal force (615.923 N) and the frictional force (36.955 N) from the previous calculations. We can use the coefficient of kinetic friction (0.06) to find the force of friction, which is equal to the coefficient multiplied by the normal force. In this case, the force of friction is 0.06 * 615.923 N = 36.955 N.

Therefore, the total force required to pull the skiers up the slope is the sum of the normal force and the force of friction, which is 615.923 N + 36.955 N = 652.878 N.

Now, we can use the equation P = F*v to calculate the motor power required. P represents power, F is the force, and v is the speed. Plugging in the values, we get P = 652.878 N * 2.5 m/s = 1632.195 W.

Therefore, the motor power required to pull 89 skiers up a 600 m slope inclined at 15° above horizontal at a speed of 2.5 m/s is approximately 1632 W. This power would need to be supplied by the T-bar tow in order to lift the skiers up the slope.