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## Homework Statement

Calculate the power that can be safely transferred by a medium carbon steel shaft of 100 mm diameter at 150 rpm ?

## Homework Equations

Assumed solid circular shaft.

## The Attempt at a Solution

Material : Medium Carbon steel t=580 MPa y= 50 mm k=6 ( table 9 live load varying)

T= Torque

J= polar moment of inertia for a solid circular section = pid^4/32

J=3.14*1 000 000 00 / 32 = 9 812 500 mm^3

tJ/ky = T = 580 * 9 812 500 / 300/1 000 = 18 970.8333 N m

150 rpm / 60 = 2.5 * 6.28 = 15.7 rad/s

18 970.8333 * 15.7 = Power = 298 kW / 745.7 * 1000 = 400 HP

Could someone please look over my answer ?