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DaraRai
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Power, Work, and an Inclined Angle...HELP ME!
A car with a mass of 1900 kg is going up a hill at a constant velocity of 27 meters/second. Later, the same car (mass: 1900 kg) is going down the same hill at a constant velocity of 27 meters/second. The frictional force and air resistence are the same going up the hill and going down the hill. The angle of the hill (inclined) is unknown. The horsepower of the car when it goes down hill is 47 horsepower more than the power going uphill. WHAT IS THE DEGREE OF THE HILL'S ANGLE?
Power = K, so mgh = 1/2mv^2
W = Fdcos*angle*
Power = Work/time = force(velocity)
The farthest I got was making two free-body diagrams -- one of the car going uphill and one of the car coming downhill.
Homework Statement
A car with a mass of 1900 kg is going up a hill at a constant velocity of 27 meters/second. Later, the same car (mass: 1900 kg) is going down the same hill at a constant velocity of 27 meters/second. The frictional force and air resistence are the same going up the hill and going down the hill. The angle of the hill (inclined) is unknown. The horsepower of the car when it goes down hill is 47 horsepower more than the power going uphill. WHAT IS THE DEGREE OF THE HILL'S ANGLE?
Homework Equations
Power = K, so mgh = 1/2mv^2
W = Fdcos*angle*
Power = Work/time = force(velocity)
The Attempt at a Solution
The farthest I got was making two free-body diagrams -- one of the car going uphill and one of the car coming downhill.