A 10.0-kg block is released from rest on a quarter pipe 3.00m high. The track is frictionless except for a length (6.00m). The block travels down this track and hits a spring of force constant 2,250 N/m, and compresses the spring 0.300m from its equilibrium position before coming to rest momentarily. What is the coefficient of kinetic friction between the block and the rough surface on the 6.00m length?
Hooke's Law F=-k*deltax
The Attempt at a Solution
I plugged 2,250 N/m into Hooke's law equation along with .300m to get 675N, which I assumed was the force of the block going down the ramp. Then I plug mass, gravity, and force into the equation above F=u*mg with mass being 10kg and g being 9.81m/s/s and get 6.8 and I know the answer is .328. What am I doing wrong?