# Pre-Cal help

1. Jan 20, 2005

This should be rather easy for the rest of you .. but somehow I can't remember what to do.

solve
[ (x-6) (x+7) ] / (x-2) is greater than or equal to 0

and

solve

log(base three)x + log(base three)(x-6) = 3

ty in advance =)

2. Jan 20, 2005

what have you done so far?

$$\frac{(x-6)(x+7)}{x-2} \geq 0$$
what are the critical numbers( make numerator 0 or denominator 0)

Then form your test intervals and you get the answer.

for $$\log_3x + \log_3(x-6) = 3$$ use log rules

hint: $$\log_bxy = log_bx + log_by$$

Last edited: Jan 20, 2005