# Pre calculus, help i CANT solve this problems

1. Oct 15, 2007

### jubej

hello! Im a studen from sweden and i having some troble solves this kind of problems. i have tried but the book its really bad to expleain. and i really have to know this for the comming exan, so if anyone could help me i really be so happy :)

here are some stuff i have hard time solving:

1) z^4=16i
2) 2z³ - 3z² + 2z -3 = 0

thnx again for any help

2. Oct 15, 2007

### rocomath

are those 2 separate problems or do i solve for 1 and apply it to 2?

1 - clarify question or how do you get an imaginary number?

$$\sqrt{-X}=\sqrt{X}i$$

2 - factor out a common term, hint z^2

3. Oct 15, 2007

### jubej

there are 2 separate problems.

the first one its so hard i dont where to start. or how to solve it

and the second one ill start to factor out term z² and see what happens thnx.

4. Oct 15, 2007

### jubej

i cant factor out 2² in 2)

because : 2z³ - 3z² + 2z -3 = 0 has 2z so its not and z² type.
what to do?

5. Oct 15, 2007

### rocomath

not 2^2 but z^2, you eventually get

$$z^{2}(2z-3)+(2z-3)=0$$

what would your next step be?

6. Oct 15, 2007

### jubej

that would be maybe

z² = - (2z - 3)/(2z - 3)
z² = -1

its that right?

7. Oct 15, 2007

### rocomath

$$z^{2}(2z-3)+(2z-3)=0$$

there is an implied one infront of the 2nd parenthesis

so

$$z^{2}(2z-3)+1(2z-3)=0$$

pull out a common term of 2z-3

$$(z^{2}+1)(2z-3)=0$$

yes?

8. Oct 17, 2007

### HallsofIvy

Do you know how to put a complex number in "polar form"?

Do you know DeMoivre's theorem? Those are necessary for problem 1.