Precipitate question

Question as posed in my text:

Q: The solubility product of calcium hydroxide, Ca(OH)2, is 7.9 x 10^-6 at 25 deg. celcius. Will a precipitate form when 100mL of 0.10 mol/L of CaCl2 solution and 50.0 mL of 0.070 mol/L of NaOH solution are combined?

My answer:

CaCl2 = 0.10 mol/L x 100mL/150mL = 0.067 mol/L
NaOH = 0.070 mol/L x 50mL/150mL = .023 mol/L

Ktrial = 0.067 x .023 = 1.54 x 10^-3

Therefore, since the Ktrial result is smaller than Ksp, no precipitate will form.

So this looks right to me, but something is nagging me about it...Anyone? Have I done this properly?

Thanks
 

GCT

Science Advisor
Homework Helper
1,727
0
Hi there

[tex]K=[Ca^{2+}][OH^{-}]^{2} [/tex]
 

Related Threads for: Precipitate question

  • Posted
Replies
3
Views
2K
Replies
14
Views
731
Replies
2
Views
2K
  • Posted
Replies
6
Views
15K
  • Posted
Replies
1
Views
6K
  • Posted
Replies
3
Views
1K
  • Posted
Replies
2
Views
4K
Replies
0
Views
3K

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving

Hot Threads

Top