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Predator prey model

  • Thread starter sana2476
  • Start date
  • #1
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Homework Statement


x'=x(1+2x-x2-y)
y'=y(x-a)



I need help finding the equilibrium points of this system.
 

Answers and Replies

  • #2
452
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What part are you confused about?
 
  • #3
33
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well let me state the entire problem:

Consider the predator prey type of system that's given above with a>0. The population x is prey. By itself, its rate of growth increases for small populations and then decreases for x>1. The predator is given by y, and it dies out when no prey is present. The parameter is given by a. You are asked to show that this system has a Hopf bifurcation.
i) Find the fixed point (xa,ya) with both xa,ya positive.
 
  • #4
452
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Can xa or ya be 0?
 
  • #5
33
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It doesn't say anything about that. And as a matter of fact, I was getting (0,0) as one of my equilibrium points.
 
  • #6
452
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(0,0) is an equilibrium point. Another one occures when x = 0, a 3rd one occurs when y = 0. To find the 4th equilibrium point, solve 1+2x-x2-y and x - a simultaneously.
 

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