I've done an experiment on preparing butanone by oxidation of butan-2-ol. Here are the simplified procedures. 1. Sodium dichromate-2-water were acidified by few cm^3 concentrated sulphuric acid, then the acidified dichromate and butan-2-ol were mixed. 2. Few pieces of anti-bumping granules were added and then simple distillation was carried out. Colourless distillate was obtained. 3. Add anhydrous calcium chloride to the distillate until the solid was in excess and the liquid was clear. Excess calcium chloride was then filtered. <purification of butanone> 4. Tests such as 2,4-dinitrophenylhydrazine solution test and Fehling's test were carried out. In my lab report, I need to suggest a reason why sodium dichromate was used in the experiment in place of potassium dichromate. I can't think of a reason why since both potassium dichromate and sodium dichromate are strong oxidizing agents and both can react with butan-2-ol to form butanone. Any help would be appreciated.