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## Homework Statement

Calculate how many grams of solute are necessary to prepare:

1) 100 mL of 0.1 N (Normal Solution) Ca(OH)2 (molecular weight = 74)

2) 100 mL 5% NaCl (molecular weight = 40)

## Homework Equations

Molarity = # of moles / # of liters

## The Attempt at a Solution

**1.**I set up dimensional analysis.

74g Ca(OH)2 divided by 2 since there are 2 Hydrogens = 37g Ca(OH)2 for Molecular Weight

100ml * (1 L / 1,000 mL) * (.05 mol / 1 L) * (37g / 1 mol) = 0.185g

I'm not sure if it's really .05 mol/L for Ca(OH)2. I just figured since the molarity was 0.1 N that I could divide 0.1 by 2 hydrogens to give me .05 mol/L

**2.**I honestly do not know how to even start this..