How would you prepare 1.00 L of 0.50M solution sof NiCl2 from the salt NiCl2 * 6H2O
The initial target is the number of MOLES of NiCl2. The moles you use of dry hydrated NiCl2 and the moles of the anhydrous NiCl2 would be identical. In the task you will actually weigh the hydrated compound. First determine formula weight of the sexa-hydrate.
Separate names with a comma.