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## Main Question or Discussion Point

proove that

< x0 , x1 , . . . | [xi , xj ] = 1, i, j, ∈ N_0 ; x0^p = 1 ; (xi) ^ (p ^ i) = x0 , i ∈ N > is not presentation of Prüfer group

< x0 , x1 , . . . | [xi , xj ] = 1, i, j, ∈ N_0 ; x0^p = 1 ; (xi) ^ (p ^ i) = x0 , i ∈ N > is not presentation of Prüfer group