- #1

ACLerok

- 194

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter ACLerok
- Start date

- #1

ACLerok

- 194

- 0

- #2

Ambitwistor

- 841

- 1

Originally posted by ACLerokin a month, i give a presentation about an experiment in which two objects of different mass are dropped at the same time and hit the ground at once. I am asked for a verbal and mathematical model for this experiment. Here goes my verbal model: "While mass does affect an objects weight, it does not play a role in determining the rate of fall of an object rather does the gravitational force on the object by the earth."

The "weight" of an object is defined to be the gravitational force on the object. So it is not correct to claim that the gravitational force plays a role, but the weight does not.

The correct explanation is that the gravitational force on an object is proportional to the mass of that object. From F = ma, that means that the

I am also asked to find a mathematical model but I don't know which equation corresponds with this experiment.

You can approximate the Earth's gravitational field as F = mg. Since F = ma, that means that a=g, i.e., the body always has an acceleration g (equal to about 9.81 m/s

If you want to be more accurate, the gravitational field of a planet of mass M on a body of mass m is equal to F = GMm/r

Oh yeah, and how do I take data from this experiment? I know I'm supposed to record the objects position vs. time but I amsupposed to gather the data from a Quicktime movie on the Internet. It says its at 30fps but how exactly do I analyze the data?

Well, assume the first frame is at time t=0. Then the second frame will be at time t=1/30 seconds, the third frame will be at time t=2/30=1/15 seconds, etc. From the movie, you can presumably determine how far the object has fallen in any given frame.

The data should fall roughly along the curve x = 1/2 gt

- #3

ACLerok

- 194

- 0

Originally posted by Ambitwistor

You can approximate the Earth's gravitational field as F = mg. Since F = ma, that means that a=g, i.e., the body always has an acceleration g (equal to about 9.81 m/s^{2}near the surface of the Earth), regardless of what its mass is; the mass cancels out of the equation.

If you want to be more accurate, the gravitational field of a planet of mass M on a body of mass m is equal to F = GMm/r^{2}, where G is Newton's gravitational constant and r is the distance between their centers of mass.

i'm not supposed to refer to Newton's Laws or force, just kinematics. is the mathematical model an actual equation or just some sentences or ideas?

- #4

Ambitwistor

- 841

- 1

The kinematical model is that of constant acceleration, as you say.

Share:

- Replies
- 4

- Views
- 1K

- Replies
- 3

- Views
- 781

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 13

- Views
- 21K

- Replies
- 4

- Views
- 1K

- Replies
- 4

- Views
- 574

- Replies
- 16

- Views
- 1K

- Last Post

- Replies
- 5

- Views
- 274

- Replies
- 1

- Views
- 604

- Replies
- 10

- Views
- 2K