- #1
TyErd said:ohhh! so the density of any liquid is density of water x specific gravity of the liquid?
TyErd said:in knowing that my working out is where density of water is 1000...: 80 + 1000(0.3)(9.81) - 1000(13.6)(9.81)(h) - 1000(0.72)(9.81)(0.75) = P_atmospheric. now what, i have two unknowns or do i assume P_atm is 101.325?
TyErd said:oh yeah so then what does all of that equal? it should equal the pressure at the top of the oil column so would that just be the 0 …
… because we can assume the mass of air negligible?
TyErd said:even then its incorrect. the answer is h=0.582m
Pressure can be calculated using the formula P = hρg, where P is pressure, h is height, ρ is density (specific gravity), and g is the acceleration due to gravity.
The unit of measurement for pressure in this calculation is typically expressed in pascals (Pa) or newtons per square meter (N/m²).
Yes, this calculation can be used for any type of fluid as long as the density (specific gravity) and acceleration due to gravity are known.
The height and specific gravity both play a role in determining the pressure of a fluid. As the height increases, the pressure also increases. Similarly, as the specific gravity increases, the pressure also increases.
This calculation can provide a reasonably accurate estimate of pressure, but it may not take into account certain factors such as changes in temperature or the presence of other substances in the fluid. For more precise measurements, a more comprehensive equation or experimental data may be needed.