Yup!ohhh! so the density of any liquid is density of water x specific gravity of the liquid?
ah, the question says the gage pressure (or gauge pressure) is 80 KPa …in knowing that my working out is where density of water is 1000...: 80 + 1000(0.3)(9.81) - 1000(13.6)(9.81)(h) - 1000(0.72)(9.81)(0.75) = P_atmospheric. now what, i have two unknowns or do i assume P_atm is 101.325?
yesoh yeah so then what does all of that equal? it should equal the pressure at the top of the oil column so would that just be the 0 …
no, the mass of air is very heavy, it's because the 80 KPa is given as the difference from that… because we can assume the mass of air negligible?