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Pressure (continued)

  1. Feb 25, 2008 #1
    1. The problem statement, all variables and given/known data
    Calculate the absolute and gauge pressure at the bottom of a 2.5 m deep container, if it is full of gasoline (density = 690 kg/m^3). Assume the container is open at the sea level.


    2. Relevant equations
    P = P_0 + Dhg



    3. The attempt at a solution
    P = (690 kg/m^3)(2.5m)(9.8 m/s^2) = (1.69 x 10^4 Pa)(1 kPa/10^3Pa) = 1.69 x 10 kPa (gauge pressure)
    (1.69 x 10^4 Pa) + (1.01 x 10^5 Pa) = 1.18 x 10^5 Pa (absolute pressure)

    My questions (important!):
    1. Did I do these right?
    2. Also, what is P_0 in the equation P = P_0 + Dhg?
    3. gauge pressure + 14.7 lb/in^2 = absolute pressure ----> true or false? If not, please explain.


    Thanks,

    J.
     
  2. jcsd
  3. Feb 25, 2008 #2

    Mentz114

    User Avatar
    Gold Member

    I think you've answered your own question with the formula

    P = P_0 + D.h.g

    absolute pressure = atm. pressure + gauge pressure.

    Interesting to speculate whether, if it was all underwater, the gauge pressure would be negative ?
     
  4. Feb 25, 2008 #3
    So, P is the absolute pressure, P_0 is the atm. pressure, and Dhg is the gauge pressure?
     
  5. Feb 25, 2008 #4

    Mentz114

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    Gold Member

  6. Feb 25, 2008 #5
    Okay. Now, disregarding P_0, did I do the solution correctly?
     
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