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Pressure Equilbrium Question

  1. Feb 20, 2010 #1
    Calculate Kp for H2O (g) + 1/2 O2 (g) = H2O2 (g) at 600K, using the following data:
    H2 (g) + O2 (g) = H2O2 (g) Kp = 2.3 * 10^6 at 600 K
    2H2 (g) + O2 (g) = 2H2O (g) Kp = 1.8 * 10^37 at 600 K

    2. Relevant equations
    Kp = [Products]/[Reactants]
    Kp= K(RT)^delta N

    3. The attempt at a solution
    Honestly really lost I have

    Kp = [H2O2]/[H2O][O2]^1/2

    Kp= K(RT)^delta N

    Other than that I'm thoroughly confused, can someone please explain? Thanks!
  2. jcsd
  3. Feb 20, 2010 #2
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