The pressure inside a bottle of champagne is 5.4 atm higher than the air pressure outside. The neck of the bottle has an inner radius of 0.9 cm. What is the frictional force on the cork due to the neck of the bottle?
pi x r ^(2) = area of circle
P = Mass/Area
The Attempt at a Solution
I first converted 5.4 atm to SI units (18pa). I did area = pi x 0.09m^(2). I took that and multiplied that by pressure 18pa and found the mass which is 0.477N. I did Fnet = mu x Fnormal.
18 = mu x 0.477N = 37.7 which is incorrect, anyone have an idea?